******** En Algorithme ********
Algorithme Variables i,j,k:entiers T[10],T1[10],T2[10]:tableaux d'entiers Debut j ← 1 k ← 1 Pour i de 1 Ã 10 faire Lire(T[i]) FinPour Pour i de 1 Ã 10 faire Si(T[i] mod 2 = 0)alors T1[j]← T[i] j← j+1 SiNon T2[k] ← T[i] k ← k+1 FinSi FinPour Pour i de 1 Ã j faire Ecrire(T1[i]) FinPour Pour i de 1 Ã k faire Ecrire(T2[i]) FinPour Fin
Résultat ==> 2 0 9 8 7 8 6 5 4 1 2 0 8 8 6 4 9 7 5 1
Retour vers la liste d'exercices
******** En C ********
#include<stdio.h> int main(){ int i,j=0,k=0,T[10],T1[10],T2[10]; for(i=0;i<10;i++) { printf("Enter un entier:"); scanf("%d",&T[i]); } for(i=0;i<10;i++) { if(T[i]%2 ==0){ T1[j]= T[i]; j++; }else { T2[k]=T[i]; k++; } } for(i=0;i<j;i++) printf("%d ",T1[i]); printf("\t"); for(i=0;i<k;i++) printf("%d ",T2[i]); return 0 ; }
Retour vers la liste d'exercices
******** En C++ ********
#include <iostream>
using namespace std;
int main(){
int i,j=0,k=0,T[10],T1[10],T2[10];
for(i=0;i<10;i++) {
cout<<"Enter un entier:";
cin>>T[i];
}
for(i=0;i<10;i++) {
if(T[i]%2 ==0){
T1[j]= T[i]; j++;
}else { T2[k]=T[i]; k++; }
}
for(i=0;i<j;i++)
cout<<T1[i]<<" ";
printf("\t");
for(i=0;i<k;i++)
cout<<T2[i]<<" ";
return 0 ;
}
******** En JAVA ********
import java.util.Scanner;
class Main {
public static void main(String[] args){
int [] T = new int [10];
int [] T1 = new int [10];
int [] T2 = new int [10];
int i,j=0,k=0;
Scanner sc = new Scanner (System.in);
for(i=0;i<10;i++) {
System.out.print("Enter un entier:");
T[i]= sc.nextInt();
}
for(i=0;i<10;i++) {
if(T[i]%2 ==0){
T1[j]= T[i]; j++;
}else { T2[k]=T[i]; k++; }
}
for(i=0;i<j;i++)
System.out.print(T1[ i]);
System.out.print("\t");
for(i=0;i<k;i++)
System.out.print(T2[i]);
}
}
import java.util.Scanner;
class Main {
public static void main(String[] args){
int [] T = new int [10];
int [] T1 = new int [10];
int [] T2 = new int [10];
int i,j=0,k=0;
Scanner sc = new Scanner (System.in);
for(i=0;i<10;i++) {
System.out.print("Enter un entier:");
T[i]= sc.nextInt();
}
for(i=0;i<10;i++) {
if(T[i]%2 ==0){
T1[j]= T[i]; j++;
}else { T2[k]=T[i]; k++; }
}
for(i=0;i<j;i++)
System.out.print(T1[ i]);
System.out.print("\t");
for(i=0;i<k;i++)
System.out.print(T2[i]);
}
}
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2 Commentaires
python
RépondreSupprimerWhere k is an element considering a number of} parameters together with friction. L and t are the size and thickness of the sheet steel, respectively. Harris has now knowledgeable reporters precision machining that he's been carrying metal plate in his cleat to assist with the harm. There were no limitations in burst or cuts, however he did say it "prohibited" him from sure things. At Metcam, our entire focus is on supporting our client’s business success.
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